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Showing posts with the label Solution of URI 1006

URI 1006

Solution of URI 1006 >>Average 2 #include < stdio.h >   int main ( ) {   double A, B, C, MEDIA ; scanf ( "%lf%lf%lf" , & A, & B, & C ) ; MEDIA = ( ( A * 2 ) + ( B * 3 ) + ( C * 5 ) ) / 10 ; printf ( "MEDIA = %.1lf \n " , MEDIA ) ;   return 0 ; }